A) a = 6, b = 4
B) a = 8, b = 2
C) a = 2, b = 8
D) a = 4, b = 6
Correct Answer: A
Solution :
Equation of given line in symmetric form is \[\frac{x-5}{-2}=\frac{y-1}{b-1}=\frac{z-a}{1-a}=\lambda \] ? (i) \[\therefore \] Any point on (i) can be \[\left( 5-2\lambda ,\,1+\left( b-1 \right)\lambda ,\,a+\lambda \left( 1-a \right) \right)\] ? (ii) \[\because \,\,\left( 0,\frac{17}{2},-\frac{13}{2} \right)\] 0, lies on (i) \[\Rightarrow \lambda =\frac{5}{2}\] ? (iii) Using (iii) in (ii) and comparing with given point we get a = 6, b = 4
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