JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    The treatment of \[C{{H}_{3}}MgX\] with \[C{{H}_{3}}C\equiv C-H\] produces       AIEEE  Solved  Paper-2007

    A) \[C{{H}_{3}}-\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]

    B) \[C{{H}_{4}}\]   

    C)                        \[C{{H}_{3}}-CH=C{{H}_{2}}\]    

    D) \[C{{H}_{3}}C\equiv C-C{{H}_{3}}\]

    Correct Answer: B

    Solution :

                    \[C{{H}_{3}}MgX+C{{H}_{3}}-C\equiv C-H\xrightarrow{{}}C{{H}_{4}}\]    \[\uparrow +C{{H}_{3}}-C\equiv C\,\,MgX\]


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