A) \[C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
B) \[C{{H}_{4}}\]
C) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}C\equiv C-C{{H}_{3}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}MgX+C{{H}_{3}}-C\equiv C-H\xrightarrow{{}}C{{H}_{4}}\] \[\uparrow +C{{H}_{3}}-C\equiv C\,\,MgX\]You need to login to perform this action.
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