JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
      The ionization enthalpy of hydrogen atom is\[1.312\times {{10}^{6}}J\,mo{{l}^{-1}}\]. The energy required to excite the electron in the atom from \[n=1\]to \[n=2\] is       AIEEE  Solved  Paper-2007

    A) \[7.56\times {{10}^{5}}J\,mo{{l}^{-1}}\]

    B)        \[9.84\times {{10}^{5}}J\,mo{{l}^{-1}}\]

    C)        \[8.51\times {{10}^{5}}J\,mo{{l}^{-1}}\]

    D)        \[6.56\times {{10}^{5}}J\,mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

                    \[{{E}_{2}}=\frac{-1.312\times {{10}^{6}}\times {{(1)}^{2}}}{{{(2)}^{2}}}=-3.28\times {{10}^{5}}J\,mo{{l}^{-1}}\,;\]                \[{{E}_{1}}=-1.312\times {{10}^{6}}J\,mo{{l}^{-1}}\] \[\Delta E={{E}_{2}}-{{E}_{1}}=(-3.28\times {{10}^{5}}+1.312\times {{10}^{6}})\]\[J\,mo{{l}^{-1}}=9.84\times {{10}^{5}}J\,mo{{l}^{-1}}\]


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