JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    The differential equation of the family of circles with fixed radius 5 units and centre on the line y = 2 is       AIEEE  Solved  Paper-2008

    A) \[{{\left( y-2 \right)}^{2}}y{{'}^{2}}=25-{{\left( y-2 \right)}^{2}}\]

    B) \[{{\left( x-2 \right)}^{2}}y{{'}^{2}}=25-{{\left( y-2 \right)}^{2}}\]

    C) \[\left( x-2 \right)y{{'}^{2}}=25-{{\left( y-2 \right)}^{2}}\]

    D) \[\left( y-2 \right)y{{'}^{2}}=25-{{\left( y-2 \right)}^{2}}\]

    Correct Answer: A

    Solution :

                    Equation of circle can be \[{{\left( x-a \right)}^{2}}+{{\left( y-2 \right)}^{2}}=25\]                               ? (i) \[\Rightarrow \,\,a=x+\left( y-2 \right)y'\]                           ? (ii) Using (ii) in (i), we get \[{{\left( y-2 \right)}^{2}}y{{'}^{2}}=25-{{\left( y-2 \right)}^{2}}\]


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