A) \[{{X}_{2}}Y\]
B) \[{{X}_{3}}{{Y}_{4}}\]
C) \[{{X}_{4}}{{Y}_{3}}\]
D) \[{{X}_{2}}{{Y}_{3}}\]
Correct Answer: C
Solution :
Number of effective Y in a unit cell = 4. Number of effective X in a unit cell \[=8\times \frac{\left. 2 \right|}{3}=\frac{16}{3}\]. So, formula of the compound \[{{X}_{16/3}}{{Y}_{4}}={{X}_{1/3}}{{Y}_{1/4}}={{X}_{4}}{{Y}_{3}}\]
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