A) \[\sqrt{\frac{Vg{{\rho }_{1}}}{k}}\]
B) \[\frac{Vg\left( {{\rho }_{1}}-{{\rho }_{2}} \right)}{k}\]
C) \[\sqrt{\frac{Vg\left( {{\rho }_{1}}-{{\rho }_{2}} \right)}{k}}\]
D) \[\frac{Vg{{\rho }_{1}}}{k}\]
Correct Answer: C
Solution :
The ball will acquire terminal speed in the state of equilibrium \[\therefore \,\,\,V{{\rho }_{2}}g+k{{v}^{2}}-V{{\rho }_{1}}g=0\] \[v=\sqrt{\frac{Vg({{\rho }_{1}}-{{\rho }_{2}})}{k}}\]You need to login to perform this action.
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