A) 750 K
B) 1000 K
C) 1250 K
D) 500 K
Correct Answer: A
Solution :
\[\frac{1}{2}{{X}_{2}}+\frac{3}{2}{{Y}_{2}}\xrightarrow{{}}X{{Y}_{3}}\,;\,\Delta S=50\] \[-\left[ \left( 60\times \frac{1}{2} \right)+\left( 40\times \frac{3}{2} \right) \right]=-40\,J{{K}^{-1}}\,;\,\Delta H=-30\,kJ\] \[;\,\Delta G=\Delta H-T\Delta S\] At equilibrium, \[\Delta G=0\,\,;\,\,\therefore \Delta H=T\Delta S\,\,;\,\,T=\frac{\Delta H}{\Delta S}\]\[=\frac{-30000J}{-40\,J{{K}^{-1}}}=750K\].You need to login to perform this action.
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