A) \[\frac{7}{12}m{{a}^{2}}\]
B) \[\frac{2}{3}m{{a}^{2}}\]
C) \[\frac{5}{6}m{{a}^{2}}\]
D) \[\frac{1}{12}m{{a}^{2}}\]
Correct Answer: B
Solution :
\[I={{I}_{cm}}+m{{d}^{2}}=\frac{m{{a}^{2}}}{6}+m{{\left( \frac{a}{\sqrt{2}} \right)}^{2}}=\frac{2}{3}m{{a}^{2}}\]
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