A) 0.67 J
B) 0.34 J
C) 0.16 J
D) 1.00 J
Correct Answer: A
Solution :
Using momentum conservation, \[0.5\times 2=1.5\times v\Rightarrow v=\frac{2}{3}m{{s}^{-1}}\] Loss of energy \[\left[ \left( \frac{1}{2}\times 0.5\times {{\left( 2 \right)}^{2}} \right)-\frac{1}{2}\times 1.5\times {{\left( \frac{2}{3} \right)}^{2}} \right]=1-\frac{1}{3}\]= 0.67 J
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