JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    Directions: Questions No. 91 are based on the following paragraph. Wave property of electrons implies that they will show diffraction effects. Davisson and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see figure).   If a strong diffraction peak is observed when electrons are incident at an angle 'I' from the normal to the crystal planes with distance 'd' between them (see figure), de Broglie wavelength \[{{\lambda }_{dB}}\] of electrons can be calculated by the relationship (n is an integer)     AIEEE  Solved  Paper-2007

    A) \[2\,d\sin i=n{{\lambda }_{dB}}\]            

    B) \[d\cos i=n{{\lambda }_{dB}}\]

    C) \[d\sin i=n{{\lambda }_{dB}}\]

    D) \[2d\cos i=n{{\lambda }_{dB}}\]

    Correct Answer: D

    Solution :

    For strong peak, path difference \[=2n{{\lambda }_{dB}}\]                 \[\therefore \,\,\,2d\,\cos i=n\lambda {{d}_{dB}}\]


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