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  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 \[km\,{{s}^{-1}}\], the escape velocity from the surface of the planet would be

    A) 110 \[km\,{{s}^{-1}}\]   

    B)        0.11 \[km\,{{s}^{-1}}\]  

    C)        1.1 \[km\,{{s}^{-1}}\]    

    D)        11 \[km\,{{s}^{-1}}\]

    Correct Answer: A

    Solution :

                    \[\frac{{{V}_{1}}}{{{V}_{2}}}=\sqrt{\frac{{{M}_{1}}}{{{M}_{2}}}\times \frac{{{R}_{2}}}{{{R}_{1}}}}\] \[{{V}_{1}}={{V}_{2}}\sqrt{\frac{{{M}_{1}}}{{{M}_{2}}}\times \frac{{{R}_{2}}}{{{R}_{1}}}}=11\left( km/s \right)\times \sqrt{10\times 10}\]\[=110\,km/s\]


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