A) zero
B) any even integer
C) any odd integer
D) any integer
Correct Answer: C
Solution :
\[\left| \begin{matrix} a & -b & c \\ a+1 & b+1 & c-1 \\ a+1 & b-1 & c+1 \\ \end{matrix} \right|\] \[+\left| \begin{matrix} {{(-1)}^{n+2}}a & {{(-1)}^{n+1}}b & {{(-1)}^{n}}c \\ a+1 & b+1 & c-1 \\ a-1 & b-1 & c+1 \\ \end{matrix} \right|\] \[=\left| \begin{matrix} a(1+{{(-1)}^{n}}) & (-b)(1+{{(-1)}^{n}}) & c(1+{{(-1)}^{n}}) \\ a+1 & b+1 & c-1 \\ a-1 & b-1 & c+1 \\ \end{matrix} \right|=0\]You need to login to perform this action.
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