A) greater than 4ab
B) less than 4ab
C) greater than -4ab
D) less than -4ab
Correct Answer: C
Solution :
As,\[b{{x}^{2}}+cx+a=0\]has imaginary roots So,\[{{c}^{2}}<4ab\] Now,\[3{{b}^{2}}\text{ }{{x}^{2}}+6bcx+2{{c}^{2}}\] \[=3{{(bx+c)}^{2}}{{c}^{2}}\ge \text{ }{{c}^{2}}\ge 4ab\]You need to login to perform this action.
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