2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer
    Given: \[E_{F{{e}^{3+}}/Fe}^{0}=-0.036V,E_{F{{e}^{2+}}/Fe}^{0}=-0.439V.\]The value of standard electrode potential for the change,\[Fe_{(aq)}^{3+}+{{e}^{-}}\to F{{e}^{2+}}(aq)\]will be:     AIEEE  Solved  Paper-2009

    A) -0.072 V                               

    B) 0.385 V

    C)        0.770V

    D)         -0.270V

    Correct Answer: C

    Solution :

    \[F{{e}^{3+}}+3e\to Fe,\]             \[{{E}^{o}}=-0.036V\] \[F{{e}^{2+}}+2e\to Fe,\]             \[{{E}^{o}}=0.439V\] \[F{{e}^{3+}}+e\to F{{e}^{2+}},\]             \[{{E}^{o}}=\frac{3(-0.036)-2(-0.439)}{1}\] \[=0.770V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner