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JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer
    The surface of a metal is illuminated with the light of 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. The work function of the metal is:(\[hc=\] \[1240\text{ }eV.nm\])     AIEEE  Solved  Paper-2009

    A) \[3.09\text{ }eV\]                           

    B) \[1.41\text{ }eV\]           

    C) \[1.51\text{ }eV\]           

    D)        \[1.68\text{ }eV.\]

    Correct Answer: B

    Solution :

                    \[\frac{hc}{\lambda }=\phi +{{(KE)}_{\max }}\] \[\Rightarrow \] \[\frac{1240}{400}=\phi +1.68\] \[\Rightarrow \] \[\phi =1.41\,eV\]


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