A) \[{{x}^{2}}+16{{y}^{2}}=16\]
B) \[{{x}^{2}}+12{{y}^{2}}=16\]
C) \[4{{x}^{2}}+48{{y}^{2}}=48\]
D) \[4{{x}^{2}}+64{{y}^{2}}=48\]
Correct Answer: B
Solution :
Clearly second ellipse is passing through (4, 0) so semi major axis of the ellipse is ?4?. If length of semi-minor axis is b then \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] It passes through (2, 1) So \[\frac{4}{16}+\frac{1}{{{b}^{2}}}=1\] \[\frac{1}{{{b}^{2}}}=\frac{3}{4}\] \[{{b}^{2}}=\frac{4}{3}\] \[\Rightarrow \] \[{{x}^{2}}+12{{y}^{2}}=16\]You need to login to perform this action.
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