A) 3
B) 6
C) 9
D) 12
Correct Answer: C
Solution :
Equation of tangent at (2, 3) \[\equiv x2y+4=0\] Required area \[=\int\limits_{0}^{3}{\left[ {{(y-2)}^{2}}+1-2y+4 \right]}\,dy\] \[=\int\limits_{0}^{3}{\left[ {{(y-2)}^{2}}-2y+5 \right]}\,dy\] \[=9\text{ }sq.\text{ }units\]You need to login to perform this action.
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