A) \[\sqrt{3}+1\]
B) \[\sqrt{5}+1\]
C) 2
D) \[2+\sqrt{2}\]
Correct Answer: B
Solution :
\[\left| Z-\frac{4}{z} \right|=2\] Now, \[|z|=\left| Z-\frac{4}{z}+\frac{4}{z} \right|\le 2+\frac{4}{|z|}\] \[\Rightarrow \]\[\frac{|z{{|}^{2}}-2|z|-4|z|}{|z|}\le 0\] \[\Rightarrow \]\[0<|z|\le 1+\sqrt{5}\].
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