A) 4
B) 3
C) 2
D) 1.
Correct Answer: C
Solution :
\[{{p}_{1}}={{p}_{o}}\sin 2\pi (x-1)t\] \[{{p}_{2}}={{p}_{o}}\sin 2\pi (x)t\] \[{{p}_{3}}={{p}_{o}}\sin 2\pi (x+1)t\] \[p={{p}_{1}}+{{p}_{3}}+{{p}_{2}}\] \[={{p}_{o}}\sin 2\pi (x-1)t+{{p}_{o}}\sin 2\pi (x+1)t+{{p}_{o}}\sin 2\pi ct\] \[=2{{p}_{o}}sin2\pi xt\text{ }cos2\pi t+{{p}_{o}}sin2\pi xt\] \[={{p}_{o}}sin2\pi xt[2cos\pi t+1]\] \[\Rightarrow \] \[{{f}_{beat}}=2.\]You need to login to perform this action.
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