JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer
    The shortest distance between the line \[yx=1\]and the curve\[x={{y}^{2}}\]is     AIEEE  Solved  Paper-2009

    A) \[\frac{3\sqrt{2}}{8}\]

    B)                        \[\frac{2\sqrt{3}}{8}\]   

    C)        \[\frac{3\sqrt{2}}{5}\]

    D)                        \[\frac{\sqrt{3}}{4}\]

    Correct Answer: A

    Solution :

    \[1=2y\frac{dy}{dx}\] \[\frac{dy}{dx}=\frac{1}{2y}=1\] \[\Rightarrow \] \[y=\frac{1}{2}\]\[\Rightarrow \] \[x=\frac{1}{4}\] shortest distance                 \[=\left| \frac{\frac{1}{2}-\frac{1}{4}-1}{\sqrt{2}} \right|=\frac{3}{4\sqrt{2}}=\frac{3\sqrt{2}}{8}\] Directions: Questions number 86 - 90 are Assertion- Reason type questions. Each of these questions contains two statements; Statement - 1 (Assertion) and Statement - 2 (Reason) Each of these questions also have four alternative choices, only one of which is the correct answer. You have to select the correct choice.


You need to login to perform this action.
You will be redirected in 3 sec spinner