A) A only
B) B only
C) Both A and B
D) Neither A nor B
Correct Answer: A
Solution :
\[r=k[C{{l}_{2}}][{{H}_{2}}S]\] \[\therefore \]According to\[A\to r=k[{{H}_{2}}S][C{{l}_{2}}]\] \[\therefore \]According to\[B\to r=k[C{{l}_{2}}][HS]\] Or \[{{K}_{eq}}=\frac{[{{H}^{+}}][HS]}{[{{H}_{2}}S]}\] \[[HS]={{K}_{eq}}\frac{[{{H}_{2}}S]}{{{H}^{+}}}\] \[r=k[C{{l}_{2}}]\,\,{{K}_{eq}}\,\frac{[{{H}_{2}}S]}{[{{H}^{+}}]}\] \[=K'\frac{[C{{l}_{2}}][{{H}_{2}}S]}{[{{H}^{+}}]}\] \[\therefore \] (A) OnlyYou need to login to perform this action.
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