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JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
      If sodium sulphate is considered to be completely dissociated into cations and anions in equeous solution, the change in freezing point of water\[(\Delta {{T}_{f}}),\], When 0.01 mol of sodium sulphate is dissolved in 1 kg of water, is\[({{K}_{f}}=1.86K\text{ }Kg\text{ }mo{{l}^{-1}})\]       AIEEE  Solved  Paper-2010

    A) 0.0186 K              

    B)        0.0372 K              

    C)        0.0558 K              

    D)        0.0744 K

    Correct Answer: C

    Solution :

    \[N{{a}_{2}}S{{O}_{4}}2N{{a}^{2}}+SO_{4}^{-2}\]          \[i=3\]           \[\Delta {{T}_{f}}\]                \[=i{{K}_{f}}.m\] \[=3\times 1.86\times 0.0\] \[=0.0558\text{ }K\]


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