A) -2
B) -1
C) 1
D) 2
Correct Answer: C
Solution :
Here roots of\[{{x}^{2}}x+1=0\]are\[\omega \]and\[{{\omega }^{2}}\]. \[{{(\text{ }\omega )}^{2009}}+{{({{\omega }^{2}})}^{2009}}={{(\omega )}^{2007}}\times {{(\omega )}^{2}}+\] \[{{({{\omega }^{2}})}^{2007}}\times {{({{\omega }^{2}})}^{2}}({{\omega }^{2}}+\omega )=1.\]You need to login to perform this action.
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