A) 1
B) \[\frac{2}{3}\]
C) \[\frac{3}{2}\]
D) 3
Correct Answer: A
Solution :
Function\[(\uparrow )\] \[f(x)\le f(2x)\le f(3x)\] \[1\le \frac{f(2x)}{f(x)}\le \frac{f(3x)}{f(x)}\] given that \[\frac{f(3x)}{f(x)}=1\] hence \[1\le \frac{f(2x)}{f(x)}\le 1\] hence \[\underset{x\to \infty }{\mathop{\lim }}\,\frac{f(2x)}{f(x)}=1\](by sandwich theorem)You need to login to perform this action.
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