A) \[\sqrt{41}\]
B) 21
C) 41
D) 42
Correct Answer: B
Solution :
\[P'(x)=P'(1x)\] integrate \[P(x)=P(1x)+k\] ------- (1) put\[x=1\] \[P(1)=P(0)+k\] \[41=1+k\] \[K=42\] Put in (1) \[P(x)=P(1x)+42\] ------(2) Now \[I=\int\limits_{0}^{1}{P(x)dx}\] also \[I=\int\limits_{0}^{1}{P(1-x)dx}\] \[2I=\int\limits_{0}^{1}{(P(x)+P(1-x))dx}\] using (2) \[2I=\int\limits_{0}^{1}{42}dx=42(x)_{0}^{1}\] \[I=21\]You need to login to perform this action.
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