A) 1
B) 0
C) \[-\frac{1}{2}\]
D) \[-1\]
Correct Answer: D
Solution :
\[f:R\to Rf(x)=\left\{ \begin{matrix} k-2x & x\le -1 \\ 2x+3 & x\ge -1 \\ \end{matrix} \right\}\] \[f'(x)=\left\{ \begin{matrix} -2 & x1 \\ \end{matrix} \right\}\] \[k-2x=+1\] \[k=-1\]You need to login to perform this action.
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