A) \[14\text{ }m/{{s}^{2}}\]
B) \[13\text{ }m/{{s}^{2}}\]
C) \[12\text{ }m/{{s}^{2}}\]
D) \[7.2\text{ }m/{{s}^{2}}\]
Correct Answer: A
Solution :
\[s={{t}^{3}}+5\] \[v=\frac{ds}{dt}=3{{t}^{2}}\] \[\frac{dv}{dt}=6t\] \[a=\sqrt{(a_{r}^{2}+a_{t}^{2})}\]\[=\sqrt{{{\left( \frac{{{v}^{2}}}{R} \right)}^{2}}+{{\left( \frac{dv}{dt} \right)}^{2}}}=14\,m/{{s}^{2}}\] At \[t=2s\]You need to login to perform this action.
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