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JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
      The correct order of\[E_{{{M}^{2+}}/M}^{o}\]values with negative sign for the four successive elements \[Cr,Mn,Fe\]and\[Co\]is       AIEEE  Solved  Paper-2010

    A) \[Cr>Mn>Fe>Co\]

    B) \[Mn>Cr>Fe>Co\]

    C) \[Cr>Fe>Mn>Co\]

    D) \[Fe>Mn>Cr>Co\]

    Correct Answer: B

    Solution :

    \[E_{M+28/M}^{0}\] \[Ti\] -1.67 \[\frac{V}{-1.18}\] \[Cr\] -0.91 \[\frac{Mn}{-1.18}\]
    \[Fe\] - 0.44 \[Co\] - 0.28 \[Ni\] -0.24 \[Cu\] +0.34 \[Zn\] -0.76


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