A) \[3.6\times {{10}^{-3}}m\]
B) \[5.0\times {{10}^{-3}}m\]
C) \[7.5\times {{10}^{-3}}m\]
D) \[9.6\times {{10}^{-3}}m\]
Correct Answer: A
Solution :
\[{{a}_{1}}{{v}_{1}}={{a}_{2}}{{v}_{2}}\] \[{{v}_{2}}^{2}={{v}_{1}}^{2}+2gh\] \[{{v}_{2}}^{2}={{(0.4)}^{2}}+2\times 10\times 0.2\] \[={{(0.4)}^{2}}+4\] \[{{v}_{2}}^{2}=4.61\]You need to login to perform this action.
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