A) \[\frac{(\gamma -1)}{2R}M{{v}^{2}}K\]
B) \[\frac{(\gamma -1)}{2(\gamma +1)R}M{{v}^{2}}K\]
C) \[\frac{(\gamma -1)}{2\gamma R}M{{v}^{2}}K\]
D) \[\frac{\gamma M{{v}^{2}}}{2R}K\]
Correct Answer: A
Solution :
\[\frac{1}{2}m{{v}^{2}}=\frac{n\times R\Delta T}{(\gamma -1)}\] \[\Rightarrow \,\,\,\Delta T=\frac{M{{V}^{2}}(\gamma -1)}{2R}\]
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