A) Ethyl ethanoate
B) Diethyl ether
C) 2?Butanone
D) Ethyl chloride
Correct Answer: A
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-O-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} \Theta \\ O \\ | \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\] \[-C{{l}^{-}}\downarrow \] \[C{{H}_{3}}-\underset{Ethylacetate}{\mathop{C{{H}_{2}}-O-\overset{\begin{smallmatrix} O \\ |\,| \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\]You need to login to perform this action.
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