A) \[ClC{{H}_{2}}C{{H}_{2}}C{{H}_{2}}COOH\]
B) \[C{{H}_{3}}COOH\]
C) \[HCOOH\]
D) \[C{{H}_{3}}C{{H}_{2}}CH(Cl)C{{O}_{2}}H\]
Correct Answer: D
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ \Upsilon \\ Cl \end{smallmatrix}}{\mathop{C}}\,H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH\] Presence of electron withdrawing group nearest to the carboxylic group increase the acidic strength to maximum extent
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