A) \[p=\frac{1}{2},q=\frac{3}{2}\]
B) \[p=\frac{1}{2},q=-\frac{3}{2}\]
C) \[p=\frac{5}{2},q=\frac{1}{2}\]
D) \[p=-\frac{3}{2},q=\frac{1}{2}\]
Correct Answer: D
Solution :
The given function \[f\] is continuous at \[x=0\] if \[\underset{h\to 2}{\mathop{\lim }}\,f(0-h)=f(0)=\underset{h\to 0}{\mathop{\lim }}\,f(0+h)\] \[\Rightarrow \,\,p+2=q=\frac{1}{2}\] \[\Rightarrow \,\,p=-\frac{3}{2},q=\frac{1}{2}\]You need to login to perform this action.
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