A)
B)
C)
D)
Correct Answer: A
Solution :
\[\frac{d\theta }{dt}=-k(\theta -{{\theta }_{0}})\] \[\int\limits_{{{\theta }_{0}}}^{\theta }{\frac{d\theta }{\theta -{{\theta }_{0}}}=-k}\int\limits_{0}^{t}{dt}\] ln \[(\theta -{{\theta }_{0}})=-kt+C\] So graph is straight line.You need to login to perform this action.
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