A) \[1.73\times {{10}^{-5}}\] M/min
B) \[3.47\times {{10}^{-4}}\] M/min
C) \[3.47\times {{10}^{-5}}\] M/min
D) \[1.73\times {{10}^{-4}}\] M/min
Correct Answer: B
Solution :
\[K=\frac{1}{40}In\frac{0.1}{0.025}=\frac{1}{40}In4\] \[R=K{{[A]}^{1}}=\frac{1}{40}In4.(0.1)=\frac{2In2}{40}(0.1)=3.47\times {{10}^{-4}}\]You need to login to perform this action.
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