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JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    \[{{K}_{f}}\] for water is \[1.86\]K kg \[mo{{l}^{-1}}\]. If your automobile radiator holds \[1.0\] kg of water, how may grams of ethylene glycol \[({{C}_{2}}{{H}_{6}}{{O}_{2}})\] must you add to get the freezing point of the solution lowered to \[-{{2.8}^{o}}C\]?   AIEEE  Solved  Paper-2012

    A) 72 g                                          

    B) 93 g

    C) 39 g                                          

    D) 27 g

    Correct Answer: B

    Solution :

                 \[\Delta {{T}_{f}}=i\times {{k}_{f}}\times m\] \[2.8=1\times 1.86\times \frac{x}{62\times 1}\] \[x=\frac{2.8\times 62}{1.86}=93\,\,gm\]


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