JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    Statement-1: The sum of the series 1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) + .... + (361 + 380 + 400) is 8000. Statement-2: \[\sum\limits_{k=1}^{n}{({{k}^{3}}-{{(k-1)}^{3}}={{n}^{3}}}\], for any natural number n.   AIEEE  Solved  Paper-2012

    A) Statement-1 is false, Statement-2 is true.

    B) Statement-1 is true, statement-2 is true; statement-2 is a correct explanation for Statement-1.

    C) Statement-1 is true, statement-2 is true; statement-2 is not a correct explanation for Statement-1.

    D) Statement-1 is true, statement-2 is false.

    Correct Answer: B

    Solution :

                 \[{{T}_{n}}={{(n-1)}^{2}}+(n-1)n+{{n}^{2}}=\frac{{{(n-1)}^{3}}-{{n}^{3}})}{(n-1)-n}\]              \[={{n}^{3}}-{{(n-1)}^{3}}\] \[{{T}_{1}}={{1}^{3}}-{{0}^{3}}\] \[{{T}_{2}}={{2}^{3}}-{{1}^{3}}\] \[\vdots \] \[\phi \] \[{{S}_{20}}={{20}^{3}}-{{0}^{3}}=8000\]


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