A)
B)
C)
D)
Correct Answer: C
Solution :
\[F=ma={{F}_{0}}{{e}^{-bt}}\] \[\frac{dv}{dt}=\frac{{{F}_{0}}}{m}{{e}^{-bt}}\] \[\int\limits_{0}^{v}{dv}=\frac{{{F}_{0}}}{m}\int\limits_{0}^{t}{{{e}^{-bt}}dt}\] \[v=\frac{{{F}_{0}}}{m}\left[ \frac{{{e}^{-bt}}}{-b} \right]_{0}^{t}\] \[v=\frac{{{F}_{0}}}{mb}\left( 1-{{e}^{-bt}} \right)\]You need to login to perform this action.
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