JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    An ellipse is drawn by taking a diameter of the circle \[{{(x-1)}^{2}}+{{y}^{2}}=1\] as its semi-minor axis and a diameter of the circle \[{{x}^{2}}+{{(y-2)}^{2}}=4\] is semi-major axis. If the centre of the ellipse is at the origin and its axes are the coordinate axes, then the equation of the ellipse is :   AIEEE  Solved  Paper-2012

    A) \[4{{x}^{2}}+{{y}^{2}}=4\]                              

    B) \[{{x}^{2}}+4{{y}^{2}}=8\]

    C) \[4{{x}^{2}}+{{y}^{2}}=8\]                              

    D) \[{{x}^{2}}+4{{y}^{2}}=16\]

    Correct Answer: D

    Solution :

                 \[\Rightarrow \]Length of semi minor axis is \[=2\]              Length of semi major axis is 4 then equation of ellipse is \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{4}=1\] \[{{x}^{2}}+4{{y}^{2}}=16\]


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