A) \[\frac{3V}{m}\]
B) \[\frac{6V}{m}\]
C) \[\frac{9V}{m}\]
D) \[\frac{12V}{m}\]
Correct Answer: B
Solution :
\[\frac{{{E}_{o}}}{{{B}_{o}}}=c\] \[\Rightarrow \] \[{{E}_{o}}=c{{B}_{o}}\] \[=(20\times {{10}^{-9}}T)3\times {{10}^{8}}\] \[=6\text{ }V/m.\]
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