JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
      Given: \[E_{C{{r}^{3+}}/Cr}^{0}=-0.74V;\]           \[E_{MnO_{4}^{-}/M{{n}^{2+}}}^{0}\text{=}1.51\text{ }V\] \[E_{C{{r}_{2}}o_{7}^{2-}/C{{r}^{3+}}}^{0}\text{=}1.33\text{ }V;\]            \[E_{Cl/C{{l}^{-}}}^{0}\text{=}1.36\text{ }V\] Based on the data given above, strongest oxidizing agent will be:     AIEEE Solevd Paper-2013

    A) \[C{{l}^{-}}\]      

    B)        \[C{{r}^{3+}}\]  

    C)        \[M{{n}^{2+}}\]               

    D)        \[MnO_{4}^{-}\]

    Correct Answer: D

    Solution :

    \[MnO_{4}^{-}\]is strongest oxidizing agent.


You need to login to perform this action.
You will be redirected in 3 sec spinner