A) 2500
B) 3000
C) 3500
D) 4500
Correct Answer: C
Solution :
\[\frac{dp}{dx}=100-12\sqrt{x}\] \[P=100x-12.\frac{2}{3}{{x}^{3/2}}+C\] \[P=100x-8{{x}^{3/2}}+C\] ? (1) Given if \[x=0,\text{ }P=2000\] \[\Rightarrow \]\[C=2000\] So, (1) becomes \[P=100\text{ }x-8{{x}^{3/2}}+2000\] If\[x=25\](is 25 move workers) \[P=100\times 25-8\times {{({{5}^{2}})}^{3/2}}+2000\] \[=2500-1000+2000=3500\]You need to login to perform this action.
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