A) \[{{x}^{2}}+{{y}^{2}}-6y-7=0\]
B) \[{{x}^{2}}+{{y}^{2}}-6y+7=0\]
C) \[{{x}^{2}}+{{y}^{2}}-6y-5=0\]
D) \[{{x}^{2}}+{{y}^{2}}-6y+5=0\]
Correct Answer: A
Solution :
Co-ordinate of Foci are (ae, 0); (−ae, 0) \[e=\sqrt{1-\frac{9}{16}}\] \[\Rightarrow \] \[e=\frac{\sqrt{7}}{4}\] Co-ordinate of Foci are \[(\sqrt{7},\,0);\,\,(-\sqrt{7},\,0)\] \[R=\sqrt{7+9}=4\] \[{{(x-0)}^{2}}+{{(y-3)}^{2}}={{4}^{2}}\] \[{{x}^{2}}+{{y}^{2}}-6y+9=16\] \[\therefore \] \[{{x}^{2}}+{{y}^{2}}-6y-7=0\]You need to login to perform this action.
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