A) 9
B) 36
C) 18
D) \[\frac{27}{4}\]
Correct Answer: A
Solution :
\[y=\sqrt{x}\] and \[2y-x+3=0\] \[\int\limits_{0}^{9}{\sqrt{x}}dx-\int\limits_{3}^{9}{\left( \frac{x-3}{2} \right)}dx\] \[\left( \frac{{{x}^{3/2}}}{3/2} \right)_{0}^{9}-\left[ \frac{\left( \frac{{{x}^{2}}}{2}-3x \right)}{2} \right]_{3}^{9}\] \[\Rightarrow \]9 square unitsYou need to login to perform this action.
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