JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    Two capacitors\[{{C}_{1}}\]and\[{{C}_{2}}\]are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then:     AIEEE Solevd Paper-2013

    A) \[5{{C}_{1}}=3{{C}_{2}}\]                             

    B) \[3{{C}_{1}}=5{{C}_{2}}\]             

    C)        \[3{{C}_{1}}+5{{C}_{2}}=0\]

    D)        \[9{{C}_{1}}=4{{C}_{2}}\]

    Correct Answer: B

    Solution :

    Potential = 0 on connecting them together i.e.\[Q=0\] i.e.\[{{C}_{1}}{{V}_{1}}={{C}_{2}}{{V}_{2}}\][capacitance is positive but they are connected with opposite polarity] \[120\text{ }{{C}_{1}}=200\text{ }{{C}_{2}}\] \[3{{C}_{1}}=5{{C}_{2}}\]


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