A) \[53.6\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[48.6\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[58.5\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[60.5\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: A
Solution :
\[0.3010=\frac{Ea}{2.303R}\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right]\] \[\Rightarrow \]\[0.3010=\frac{Ea}{2.303\times 8.314\times {{10}^{-3}}}\left( \frac{310-300}{310\times 300} \right)\] \[{{E}_{a}}=53.6\text{ }kJ\text{ }mol\]
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