A) \[v/2\]
B) \[2v\]
C) \[v/3\]
D) \[3v\]
Correct Answer: C
Solution :
Here \[{{m}_{1}}=m\] \[{{m}_{2}}=2m\] \[{{v}_{1}}=v\] \[{{v}_{2}}=0\] Let the speed of the system after collison = v Using the principle of conservation of linear momentum \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\] \[\Rightarrow \] \[v=\frac{mv+2m\times 0}{m+2m}=\frac{mv}{3m}=\frac{v}{3}\]You need to login to perform this action.
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