A) 25
B) 49
C) 59
D) 98.
Correct Answer: D
Solution :
The given reaction is: \[NaOH+{{H}_{3}}P{{O}_{4}}\to Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\] Molecular mass ofH3P04 is 98. As there is only one electron change involved therefore, equivalent 98 weight of \[{{H}_{3}}P{{O}_{4}}\] in this reaction is, \[\frac{98}{1}=98\]You need to login to perform this action.
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