A) voltage
B) current
C) power
D) frequency.
Correct Answer: B
Solution :
In a step-down transformer, the voltage in the secondary is less than the voltage in the primary circuit. That is \[{{\varepsilon }_{2}}<{{\varepsilon }_{1}}\]. Since we know for an ideal transformer \[{{\varepsilon }_{2}}{{i}_{2}}={{\varepsilon }_{1}}{{i}_{1}}\] \[\Rightarrow \] \[{{i}_{2}}=\frac{{{\varepsilon }_{1}}}{{{\varepsilon }_{2}}}{{i}_{1}}\] \[\Rightarrow \] \[{{i}_{2}}>{{i}_{1}}\] \[\therefore \] The current in the secondary increases.
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